#yyds干货盘点# 面试必刷TOP101：链表中的节点每k个一组翻转

{1,2,3,4,5},2

{2,1,4,3,5}

{},1

{}

import java.util.*;
public class Solution {
    public ListNode reverseKGroup (ListNode head, int k) {
        //找到每次翻转的尾部
        ListNode tail = head;
        //遍历k次到尾部 
        for(int i = 0; i < k; i++){ 
            //如果不足k到了链表尾，直接返回，不翻转
            if(tail == null) 
                return head;
            tail = tail.next; 
        }
        //翻转时需要的前序和当前节点
        ListNode pre = null; 
        ListNode cur = head;
        //在到达当前段尾节点前
        while(cur != tail){ 
            //翻转
            ListNode temp = cur.next; 
            cur.next = pre;
            pre = cur;
            cur = temp;
        }
        //当前尾指向下一段要翻转的链表
        head.next = reverseKGroup(tail, k); 
        return pre;
    }
}